((3x^2)/4)-x=-1/2

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Solution for ((3x^2)/4)-x=-1/2 equation: 


x in (-oo:+oo)

(3*x^2)/4-x = -1/2 // + -1/2

(3*x^2)/4-x-(-1/2) = 0

(3*x^2)/4-x+1/2 = 0

3/4*x^2-x+1/2 = 0

DELTA = (-1)^2-(1/2*3/4*4)

DELTA = -1/2

DELTA < 0

x belongs to the empty set

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